(x^2+x+1)(x-1)=

Solution for (x^2+x+1)(x-1)= equation:

Simplifying
(x2 + x + 1)(x + -1) = 0

Reorder the terms:
(1 + x + x2)(x + -1) = 0

Reorder the terms:
(1 + x + x2)(-1 + x) = 0

Multiply (1 + x + x2) * (-1 + x)
(1(-1 + x) + x(-1 + x) + x2(-1 + x)) = 0
((-1 * 1 + x * 1) + x(-1 + x) + x2(-1 + x)) = 0
((-1 + 1x) + x(-1 + x) + x2(-1 + x)) = 0
(-1 + 1x + (-1 * x + x * x) + x2(-1 + x)) = 0
(-1 + 1x + (-1x + x2) + x2(-1 + x)) = 0
(-1 + 1x + -1x + x2 + (-1 * x2 + x * x2)) = 0
(-1 + 1x + -1x + x2 + (-1x2 + x3)) = 0

Combine like terms: 1x + -1x = 0
(-1 + 0 + x2 + -1x2 + x3) = 0
(-1 + x2 + -1x2 + x3) = 0

Combine like terms: x2 + -1x2 = 0
(-1 + 0 + x3) = 0
(-1 + x3) = 0

Solving
-1 + x3 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + x3 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + x3 = 0 + 1
x3 = 0 + 1

Combine like terms: 0 + 1 = 1
x3 = 1

Simplifying
x3 = 1

Reorder the terms:
-1 + x3 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + x3 = 0

The solution to this equation could not be determined.